l=(44+8)/2=26 b=(44-8)/2=18 2p=18+52=70cm
134) Triangolo isoscele
Somma e differenza tra due valori, quindi:
ciascun lato obliquo $l= \dfrac{44+8}{2} = \dfrac{52}{2} = 26\,cm;$
base $b= \dfrac{44-8}{2} = \dfrac{36}{2} = 18\,cm;$
perimetro $2p= b+2×l = 18+2×26 = 18+52 = 70\,cm.$