Seconda media un modo facile per farli per favore

qualunque numero, escluso lo zero, elevato a zero fa 1

quindi 3^0=1

(1+1/2-12/13) = 26+13-24/26 =(15/26):x

3/2-2/3= 9-4 /6 = 5/6

(3/5 +2)= 3+10 /5 13/5

15/26 : X = 5/6*5/13   

15/26 : X = 25/ 78

X = 25/78 *26/15  =  5/9

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175)

$\left(3^0+\dfrac{1}{2}-\dfrac{12}{13}\right) : x = \left(\dfrac{3}{2}-\dfrac{2}{3}\right) : \left(\dfrac{3}{5}+2\right)$

$\left(1+\dfrac{1}{2}-\dfrac{12}{13}\right) : x = \left(\dfrac{9-4}{6}\right) : \left(\dfrac{3+10}{5}\right)$

$\left(\dfrac{26+13-24}{26}\right) : x = \dfrac{5}{6} : \dfrac{13}{5}$

$\dfrac{15}{26} : x = \dfrac{5}{6} : \dfrac{13}{5}$

$x= \dfrac{\cancel{15}^3}{\cancel{26}_2}·\dfrac{\cancel{13}^1}{\cancel5_1} : \dfrac{5}{6}$

$x= \dfrac{3}{2}·\dfrac{1}{1}·\dfrac{6}{5}$

$x= \dfrac{3}{\cancel2_1}\dfrac{\cancel6^3}{5}$

$x= \dfrac{3}{1}·\dfrac{3}{5}$

$x= \dfrac{9}{5}$