Xfraz4+1fraz4-2xfraz3+1fraz3=3fraz12-5xfraz12-(2+x)
Xfraz4+1fraz4-2xfraz3+1fraz3=3fraz12-5xfraz12-(2+x)
Xfraz4+1fraz4-2xfraz3+1fraz3=3fraz12-5xfraz12-(2+x)
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La riscrivo:
$\dfrac{x}{4}+\dfrac{1}{4}-\dfrac{2}{3}x+\dfrac{1}{3} = \dfrac{3}{12}-\dfrac{5}{12}x -(2+x)$
mcm dei denominatori = 12 quindi moltiplica tutto per 12 ed elimini i denominatori:
$3x +3 -8x+4 = 3 -5x -12(2+x)$
$-5x+7= 3-5x-24-12x$
$-5x+7 = -21-17x$
raggruppa a sinistra i valori con incognita e a destra i valori noti cambiando il segno se passi l'uguale:
$-5x +17x = -21-7$
$12x = -28$
dividi ambo le parti per 12 così isoli l'incognita:
$\dfrac{\cancel{12}x}{\cancel{12}} = -\dfrac{\cancel{28}^7}{\cancel{12}_3}$
$x = -\dfrac{7}{3}$ $(\approx{-2,\overline3}).$
Xfraz4+1fraz4-2xfraz3+1fraz3=3fraz12-5xfraz12-(2+x)
Ma è arabo?