(2·x^3 - 1)^2= 4·x^6 - 4·x^3 + 1
∫(4·x^6 - 4·x^3 + 1)dx=
=4·x^7/7 - x^4 + x=
=x·(4·x^6 - 7·x^3 + 7)/7 + C
Sviluppo algebrico
$ \int (2x^3-1)^2 \, dx = \int 4x^6 - 4x^3 + 1 \, dx = \frac{4x^7}{7} - x^4 + x + c $
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