4^(1 + 2·x)/8^x= 2^(x + 2) = 4·2^x
2^x=e^(x·LN(2))
∫(2^(x + 2))dx=4·∫(e^(x·LN(2)))dx =
Ti devi ricordare che:
∫(e^(b·x))dx= e^(b·x)/b
=4·e^(x·LN(2))/LN(2) = 2^(x + 2)/LN(2) + C
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