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Risolvi esercizio n 18 passo per passo grazie

  

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Autore

@ludoste77 ....grazie, ma che ci fai in piedi a quest'ora?

14 Risposte



3

Mi é ben chiaro che vuoi uno svolgimento puramente numerico.

 

18

[2*(-2)^(-1/2)]/[(-2)^2 - (-1/2)^2] - (-2)/((-2) - (-1/2)) =

= 2/(4 - 1/4) + 2/(-2 + 1/2) =

= 2 : ((16-1)/4) + 2:(-3/2) =

= 2*4/15 - 2*2/3 =

= 8/15 - 4/3 =

= (8 - 20)/15 = -12/15 = -4/5

@eidosm 👍👌👍



1
image

2/(4-1/4)- (-2/(-2+1/2))

2*4/15-4/3

8/15-4/3 

(8-20)/15 

-12/15

-4/5



1
image

-7a+2ab-b^2 

+7-6-9

-9+1

-8



1
image

a^3+6a-2b^2

8+12-2*16

20-32

-12



1
image

2a^2+8b+3ab^2

8-8-6

-6

 



1
image

(-xy+3y)+(-x^2)-x^2 

-2+3+4-4

-2+3

1



1
image

9x-3x^2y-1/2

-3-1-1/2

-4-1/2 

(-8-1)/2

-9/2



1
image

2(x^2-y): (3xy+4+y^3)

2(1+1/2):(3/2+4-1/8)

3 :(11/2-1/8)

3 : ((44-1)/8)

3*8/43

24/43



1
image

x+1/(x^2y)-1/(xy^2)

-1+1/-1/3-1/-1/9

-1-3+9 

-4+9

 



1
image

-1/6*(a-2b)(a+2b)/(a^2-4b^2)

-1/6*(1/9-1)/(1/9-1)

-1/6*-8/9*-9/8

-1/6*1

-1/6



1
image

√(x^2+3xy) / (4x+7y^2)

√(4+12) / (8+28)

4/36

1/9



1
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√((6*1/9*1/2+1/6+1/4)/-2/3 * -1/2)

√((1/3+1/6+1/4)*-3/2*-1/2)

√((1/2+1/4)*3/4)

√(3/4 * 3/4) 

√9/16

3/4 



1
image

(2/(1/6-1/9)*(1/6+1)/(-1/3-2)

2/(1/18)*7/6*-3/7

2*18*-1/2

18*-1

-18 



1
image

(-9+6+7)/-24 : (18/(-6-12))

-4/24 / -1 

-1/6 / -1

1/6



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