E' solo un esercizio di pazienza
A = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15]
B = [1,3,5,15]
C = [0,3,5,8,10]
allora
A & B = [1,3,5,15] essendo B contenuto in A
A U B - C = [1,2,4,6,7,9,11,12,13,14,15]
sono gli elementi di A U B che non appartengono a C
* A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}
* B = {1, 3, 5, 15}
* A ∪ B = A
* A ∩ B = B
* C = {0, 3, 5, 8, 10}
* A ∪ B - C = A - C =
= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15} \ {0, 3, 5, 8, 10} =
= {1, 2, 4, 6, 7, 9, 11, 12, 13, 14, 15}
Vedi ai link
http://www.wolframalpha.com/input?i=table%5Bk%2C%7Bk%2C1%2C15%7D%5D
http://www.wolframalpha.com/input?i=divisors+15
http://www.wolframalpha.com/input?i=%7B1%2C2%2C3%2C4%2C5%2C6%2C7%2C8%2C9%2C10%2C11%2C12%2C13%2C14%2C15%7D%5C%7B0%2C3%2C5%2C8%2C10%7D