Proprietà della radice quadrata

√[(3/4)^2+5]^2:[(3/4)^5+1]^2=

√[(3/4)^7]^2:[(3/4)^6]^2 =

√(3/4)^14:(3/4)^12 =

√(3/4)^14-12 = √(3/4)^2 = [(3/4)^2]^1/2 = 3/4

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$\small \sqrt{\left[\left(\dfrac{3}{4}\right)^2 : \left(\dfrac{3}{4}\right)^5\right]^2 : \left[\left(\dfrac{3}{4}\right)^5·\dfrac{3}{4}\right]^2}=$

$\small =\sqrt{\left[\left(\dfrac{3}{4}\right)^{2+5}\right]^2 : \left[\left(\dfrac{3}{4}\right)^{5+1}\right]^2}=$

$\small =\sqrt{\left[\left(\dfrac{3}{4}\right)^7\right]^2 : \left[\left(\dfrac{3}{4}\right)^6\right]^2}=$

$\small =\sqrt{\left(\dfrac{3}{4}\right)^{7·2} : \left(\dfrac{3}{4}\right)^{6·2}}=$

$\small =\sqrt{\left(\dfrac{3}{4}\right)^{14} : \left(\dfrac{3}{4}\right)^{12}}=$

$\small =\sqrt{\left(\dfrac{3}{4}\right)^{14-12}}=$

$\small =\sqrt{\left(\dfrac{3}{4}\right)^2}=$

$\small =\sqrt{\dfrac{9}{16}}$

$\small = \dfrac{3}{4}$

oppure elimini la radice quadrata con l'esponente e rimane:

$\small =\dfrac{3}{4}$

√( (3/4)^14 : (3/4)^12 )

√(3/4)^(14-12)

(3/4)^(2/2) 

(3/4)^1

3/4