A(abcd)=36^2=1296 A2=1296*4/9=576 A=1296-576=720cm2
l2=V 576=24 2p2=24*4=96 2p1=36*4=144 2P=144+96=240cm
========================================================
Parte colorata:
perimetro $2p= 4(36+\sqrt{\dfrac{4}{9}×36^2} = 4(36+\dfrac{2}{3}×36 = 4(36+24) = 4×60=240\,cm;$
area $A= 36^2-\dfrac{4}{9}×36^2 = 1296-\dfrac{4}{9}×1296 = 1296-576 = 720\,cm^2.$