Mi potete aiutare con la 301? Grazie
Mi potete aiutare con la 301? Grazie
((9^3·2^6/18^4 - 2/3)^3·(2/9)^2)^(-3)·(72^4/9^8·(2/(27^4·9^5)))=
=((2^6·3^6/(2^4·3^8) - 2/3)^3·(2/9)^2)^(-3)·(2^12·3^8/3^16·(2/(3^12·3^10)))=
=((2^2/3^2 - 2/3)^3·(2/9)^2)^(-3)·(2^12/3^8·(2/3^22))=
=((4/9 - 2/3)^3·(2/9)^2)^(-3)·(2^13/3^30)=
=((- 2/9)^3·(2/9)^2)^(-3)·(2^13/3^30)=
=(- 2^5/3^10)^(-3)·(2^13/3^30)=
=(- 3^30/2^15)·(2^13/3^30)=
=- 1/2^2 = - 1/4