esercizio 182
esercizio 182
Es 182)
D_12 = 2ab - 2b²
D_34 = 2ab
Quindi:
D_12 - D_34 = - 2b²
182)
$ [a^2-b^2-(a^2-2ab+b^2)]-[a^2+2ab+b^2-(a^2+b^2)]$ =
= $[a^2-b^2-a^2+2ab-b^2]-[a^2+2ab+b^2-a^2-b^2]$ =
= $-2b^2+2ab -2ab$ =
= $ -2b^2$