((3^5·3)^(-2)/(3·3^3)^(-1)·(3^(-2)·3^3)·3^2)^(-1)·3^(-2)=
=((3^6)^(-2)/(3^4)^(-1)·3·3^2)^(-1)·(1/3^2)=
=(1/3^12/(1/3^4)·3·3^2)^(-1)·(1/3^2)=
=(1/3^8·3·3^2)^(-1)·(1/3^2)=
=(1/3^5)^(-1)·(1/3^2)=
=3^5·(1/3^2)= 3^3 = 27
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