num 235

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$\small \dfrac{(2+1,5-0,8)·\dfrac{5}{3}-\left(\dfrac{3}{4}+0,5+\dfrac{5}{3}\right)·0,6}{2+0,875-\dfrac{3}{2}}=$

$\small =\dfrac{\left(2+\dfrac{\cancel{15}^3}{\cancel{10}_2}-\dfrac{\cancel8^4}{\cancel{10}_5}\right)·\dfrac{5}{3}-\left(\dfrac{3}{4}+\dfrac{\cancel5^1}{\cancel{10}_2}+\dfrac{5}{3}\right)·\dfrac{\cancel6^3}{\cancel{10}_5}}{2+\dfrac{\cancel{875}^7}{\cancel{1000}_8}-\dfrac{3}{2}}=$

$\small =\dfrac{\left(2+\dfrac{3}{2}-\dfrac{4}{5}\right)·\dfrac{5}{3}-\left(\dfrac{3}{4}+\dfrac{1}{2}+\dfrac{5}{3}\right)·\dfrac{3}{5}}{2+\dfrac{7}{8}-\dfrac{3}{2}}=$

$\small =\dfrac{\left(\dfrac{20+15-8}{10}\right)·\dfrac{5}{3}-\left(\dfrac{9+6+20}{12}\right)·\dfrac{3}{5}}{\dfrac{16+7-12}{8}}=$

$\small =\dfrac{\dfrac{\cancel{27}^9}{\cancel{10}_2}·\dfrac{\cancel5^1}{\cancel3_1}-\dfrac{\cancel{35}^7}{\cancel{12}_4}·\dfrac{\cancel3^1}{\cancel5_1}}{\dfrac{11}{8}}=$

$\small =\dfrac{\dfrac{9}{2}-\dfrac{7}{4}}{\dfrac{11}{8}}=$

$\small =\dfrac{\dfrac{18-7}{4}}{\dfrac{11}{8}}=$

$\small =\dfrac{11}{4}·\dfrac{8}{11}=$

$\small =\dfrac{\cancel{11}^1}{\cancel4_1}·\dfrac{\cancel8^2}{\cancel{11}_1}=$

$\small =2$

( (2+0,7)*5/3-(9+6+20)/12*0,6 ) / (2,875-1,5)

(4,5-35/12*0,6) / 1,375

2,75/1,375 = 2,00