[3•(-8)+2•(-3^2)]/(+3)
(-24+18)/3
-6/3=-2
(3·a + 2·b^2)/(-b)
a = -8
b = -3
(3·(-8) + 2·(-3)^2)/(-(-3))=
=(-24 + 18)/(-(-3)) =(-6)/3=-2
690)
$(3a+2b^2) : (-b)$
per $a= -8; b=-3$
sostituendo:
$[(3(-8)+2(-3)^2] : [-(-3)]$
$[(-24)+2×9] : 3$
$[(-24)+18] : 3$
$[-6] : 3 = -2$