Rette numeriche
Rette numeriche
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n° 457)
Ogni tacca vale $\frac{1}{5} = 0,2$;
quindi:
$F= -10×0,2 = -2,0 ~\big(= -\frac{2}{1}\big)$;
$C= -7×0,2 = -1,4 ~\big(= -\frac{7}{5}\big)$;
$D= -2×0,2 = -0,4 ~\big(= -\frac{2}{5}\big)$;
$A= +8×0,2 = +1,6 ~\big(= +\frac{8}{5}\big)$;
$B= +12,5×0,2 = +2,5 ~\big(= +\frac{5}{2}\big)$;
$E= +15×0,2 = +3,0 ~\big(= +\frac{3}{1}\big)$.