264)
$0,2(10x-5)+0,3(x-10)=$
$= 2x-1+0,3x-3=$
$=2,3x-4$ oppure → = $\dfrac{23}{10}x-4$
posto che: $0.2=2/10=1/5$ e che $0.3=3/10$ si ricava:
$1/5(10x-5)+3/10(x-10)$
$2x-1+3/10x-3$
$23/10x-4$
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