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$5a^3 : \left(\dfrac{5}{3}a\right) -3a·(2a) -4a^2b : \left(3b\right) -6·\left(a\right)^2 =$

$= \cancel5^1a^3·\dfrac{3}{\cancel5_1a} -6a^2-4a^2\cancel{b}·\dfrac{1}{3\cancel{b}}-6a^2 =$

$= 3a^{(3-1)} -6a^2-\dfrac{4}{3}a^2-6a^2 =$

$= 3a^2 -6a^2-\dfrac{4}{3}a^2-6a^2 =$

$= \left(3-6-\dfrac{4}{3}-6\right)a^2 =$

$= \left(-9-\dfrac{4}{3}\right)a^2 =$

$= \left(\dfrac{-27-4}{3}\right)a^2 =$

$= -\dfrac{31}{3}a^2$

 

 

 

 



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