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19)

$17°45'\,6'$$'=$

$ = 17+\dfrac{\cancel{45}^3}{\cancel{60}_4}+\dfrac{6}{60^2}=$

$= 17+\dfrac{3}{4}+\dfrac{\cancel6^1}{\cancel{3600}_{600}}=$

$= 17+\dfrac{3}{4}+\dfrac{1}{600}=$

$= 17,751\overline6°.$



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20)

$35°16'\,48'$$'=$

$= 35+\dfrac{\cancel{16}^4}{\cancel{60}_{15}}+\dfrac{\cancel{48}^1}{\cancel{3600}_{75}}=$

$= 35+\dfrac{4}{15}+\dfrac{1}{75}=$

$= \dfrac{882}{25} = 35,28°$



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