$(2+\frac{7}{6}*\frac{2}{7})/x=x/(1-\frac{1}{12}*5)$
$(2+\frac{1}{3})/x=x/(1-\frac{5}{12})$
$(\frac{6+1}{3})/x=x/(\frac{12-5}{12})$
$(\frac{7}{3})/x=x/(\frac{7}{12})$
$x^2=\frac{7}{3}*\frac{7}{12}=\frac{49}{36}$
$x=\sqrt{x^2}=\sqrt{\frac{49}{36}}=\frac{7}{6}$