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229)
$\dfrac{4×2^4×(2^6)^2}{\left[\left(\dfrac{1}{2}×2^4\right)^2\right]^3}=$
$=\dfrac{2^2×2^4×2^{6×2}}{\left[\left(2^{-1}×2^4\right)^2\right]^3}=$
$=\dfrac{2^{2+4}×2^{12}}{\left[\left(2^{-1+4}\right)^2\right]^3}=$
$=\dfrac{2^6×2^{12}}{\left[\left(2^3\right)^2\right]^3}=$
$=\dfrac{2^{6+12}}{\left[2^{3×2}\right]^3}=$
$=\dfrac{2^{18}}{\left[2^6\right]^3}=$
$=\dfrac{2^{18}}{2^{6×3}}=$
$=\dfrac{2^{18}}{2^{18}}=$
$= 2^{18-18}=$
$=2^0=$
$= 1$
4·2^4 = 2^6
(2^6)^2 = 2^12
2^6·2^12/((1/2·2^4)^2)^3=
=2^18/((2^3)^2)^3=
=2^18/2^18 = 1