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Matematica 229

  

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2

4·2^4 = 2^6

(2^6)^2 = 2^12

2^6·2^12/((1/2·2^4)^2)^3=

=2^18/((2^3)^2)^3=

=2^18/2^18 = 1



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229)

$\dfrac{4×2^4×(2^6)^2}{\left[\left(\dfrac{1}{2}×2^4\right)^2\right]^3}=$

$=\dfrac{2^2×2^4×2^{6×2}}{\left[\left(2^{-1}×2^4\right)^2\right]^3}=$

$=\dfrac{2^{2+4}×2^{12}}{\left[\left(2^{-1+4}\right)^2\right]^3}=$

$=\dfrac{2^6×2^{12}}{\left[\left(2^3\right)^2\right]^3}=$

$=\dfrac{2^{6+12}}{\left[2^{3×2}\right]^3}=$

$=\dfrac{2^{18}}{\left[2^6\right]^3}=$

$=\dfrac{2^{18}}{2^{6×3}}=$

$=\dfrac{2^{18}}{2^{18}}=$

$= 2^{18-18}=$

$=2^0=$

$= 1$

@gramor grazie ☺️

@raffsasy - Grazie a te, saluti.



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