TThanks
TThanks
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Rendita posticipata
$R= 200\,euro $ rata mensile;
$i= 4,5\%;$ (tasso)
$n= 60-25 = 35\,anni$ (periodi);
$M= $ montante;
quindi:
$M= R·\dfrac{(1+i)^n-1}{i}$
$M= 200·12·\dfrac{\left(1+\frac{4,5}{100}\right)^{35}-1}{\frac{4,5}{100}}$
$M= 2400·\dfrac{\left(1+0,045\right)^{35}-1}{0,045}$
$M= 2400·\dfrac{1,045^{35}-1}{0,045}$
$M= 195591,88\,euro.$