$ log_3 3^{\frac{1}{3}} - \frac {log_3 3^{1+\frac{1}{3}}} {log_3 9} = \frac{1}{3} - \frac {1+\frac{1}{3}}{2} = \frac {1}{3} - \frac {2}{3} = -\frac {1}{3} $
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