$ 25^{log_{\frac{1}{5}} 3 + \frac {1}{log_3 5}} = $
Usiamo $ log_a b = \frac{1}{log_b a}$
$ 25^{log_{\frac{1}{5}} 3 + log_5 3} = 25^{\frac {log_5 3}{log_5 (\frac{1}{5})} + log_5 3} = 25 ^{-log_5 3 + log_5 3} = 25^0 = 1 $
Home
Profilo
Menu