$ \displaystyle\lim_{x \to 0^+} \frac{1-3ln^2 x}{1+2ln^2 x} = $
dividiamo sopra e sotto per ln² x
$ \displaystyle\lim_{x \to 0^+} \frac{\frac{1}{ln^2 x} - 3}{\frac{1}{ln^2 x}+2} = -\frac{3}{2}$
Home
Profilo
Menu