198) Parallelogramma:
Base $\small b= 30\,cm = \dfrac{5}{3}h;$
altezza $\small h= b : \dfrac{5}{3} = \cancel{30}^6×\dfrac{3}{\cancel5_1} = 6×3 =18\,cm;$
area $\small A= b×h = 30×18 = 540\,cm^2.$
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