Spiegare e argomentare.
$ M = \frac{\int_0^1 \frac{1}{x+1} \, dx} {1} = \left. ln(x+1) \right|_0^1 = ln(2)$
$ f(c) = M $
$ \frac{1}{c+1} = ln(2)$
$ ln(2) \cdot c + ln(2) = 1$
$ c = \frac{1-ln(2)}{ln(2)}$
Home
Profilo
Menu