Spiegare e argomentare.
$ M = \frac{\int_1^9 \frac{1}{\sqrt{x}} \, dx} {9-1} = \left. \frac{2\sqrt{x}}{8} \right|_1^9 = \frac{4}{8} = \frac{1}{2}$
$ f(c) = M $
$ \frac{1}{\sqrt{c}} = \frac{1}{2}$
$ \sqrt{c} = 2$
$ c = 4$
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