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4
20250219 184634

@rocchino grazie mille ☺️

prego

@rocchino 👍👌👍



3
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√8/3*11/4-2/9

√22/3-2/9

√66/9-2/9 

√64/9 = 8/3 



3
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√(10+6-3)/12*9/26+3/16

√13/12*9/26+3/16

√9/24+3/16 

√(18+9)/48

√27/48

3√3 / 4√3 

3/4 



2

181/1)

$\small \sqrt{\left(2+\dfrac{2}{3}\right)×\dfrac{11}{4}-\dfrac{2}{9}}= $

$\small =\sqrt{\left(\dfrac{6+2}{3}\right)×\dfrac{11}{4}-\dfrac{2}{9}}= $

$\small =\sqrt{\dfrac{\cancel8^2}{3}×\dfrac{11}{\cancel4_1}-\dfrac{2}{9}}= $

$\small =\sqrt{\dfrac{2}{3}×\dfrac{11}{1}-\dfrac{2}{9}}= $

$\small =\sqrt{\dfrac{22}{3}-\dfrac{2}{9}}= $

$\small =\sqrt{\dfrac{66-2}{9}}= $

$\small =\sqrt{\dfrac{64}{9}}= \dfrac{8}{3}$

@gramor 👍👌👍



2

181/2)

$\small \sqrt{\left(\dfrac{5}{6}+\dfrac{1}{2}-\dfrac{1}{4}\right)×\dfrac{9}{26}+\dfrac{3}{16}}=$

$\small =\sqrt{\left(\dfrac{10+6-3}{12}\right)×\dfrac{9}{26}+\dfrac{3}{16}}=$

$\small =\sqrt{\dfrac{\cancel{13}^1}{\cancel{12}_4}×\dfrac{\cancel9^3}{\cancel{26}_2}+\dfrac{3}{16}}=$

$\small =\sqrt{\dfrac{1}{4}×\dfrac{3}{2}+\dfrac{3}{16}}=$

$\small =\sqrt{\dfrac{3}{8}+\dfrac{3}{16}}=$

$\small =\sqrt{\dfrac{6+3}{16}}=$

$\small =\sqrt{\dfrac{9}{16}}= \dfrac{3}{4}$

@gramor 👍👌👍

@remanzini_rinaldo - Grazie Rinaldo, buona giornata.



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