Grazie mille

no 183.     {moltiplicazione    3/10 x 30/4 = 3 x 3 / (1 x  4  ) = 9/4}

radicequadrata[1 + (6/10 + 7/10) : 13/20 - 9/4 + (10/4 + 3/4)] =

= radicequadrata[1 + 13/10 x 20/13 - 9/4 + 13/4] ; 

{prima la moltiplicazione  13/10 x 20/13 = 2/1 = 2}.

= radicequadrata[1 + 2 - 9/4 + 13/4] =

= radicequadrata[4/4 + 8/4 - 9/4 + 13/4]=

= radicequadrata[16/4] =

= radicequadrata[4] = 2.

Ciao @sarannn  

183)

$\small \sqrt{1+\left(\dfrac{3}{5}+\dfrac{7}{10}\right) : \dfrac{13}{20}-\dfrac{3}{10}·\dfrac{30}{4}+\left(\dfrac{5}{2}+\dfrac{3}{4}\right)}=$

$\small =\sqrt{1+\left(\dfrac{6+7}{10}\right) · \dfrac{20}{13}-\dfrac{3}{\cancel{10}_1}·\dfrac{\cancel{30}^3}{4}+\left(\dfrac{10+3}{4}\right)}=$

$\small =\sqrt{1+\dfrac{\cancel{13}^1}{\cancel{10}_1} · \dfrac{\cancel{20}^2}{\cancel{13}_1}-\dfrac{3}{1}·\dfrac{3}{4}+\dfrac{13}{4}}=$

$\small =\sqrt{1+\dfrac{1}{1} · \dfrac{2}{1}-\dfrac{9}{4}+\dfrac{13}{4}}=$

$\small =\sqrt{1+2-\dfrac{9}{4}+\dfrac{13}{4}}=$

$\small =\sqrt{3-\dfrac{9}{4}+\dfrac{13}{4}}=$

$\small =\sqrt{\dfrac{12-9+13}{4}}=$

$\small =\sqrt{\dfrac{16}{4}}=$

$\small =\sqrt4= 2$