Potete aiutarmi con questi 2 problemi sulle circonferenze? Grazie in anticipo!
Potete aiutarmi con questi 2 problemi sulle circonferenze? Grazie in anticipo!
Ex 144
2·pi·r + 4·r
per r=12 cm:
2·pi·12 + 4·12 = (24·pi + 48 ) cm=123.398 cm
--------------
pi·r^2 + (2·r)^2
pi·12^2 + (2·12)^2= (144·pi + 576) cm^2=1028.389 cm^2
EX 145
2·pi·r/2 + 2·pi·(r/2)
r=14 cm
2·pi·14/2 + 2·pi·(14/2) = 28·pi cm
--------------------------
pi·r^2/2
r = 14 cm
pi·14^2/2 = 98·pi cm^2
144)
Perimetro:
$\small 2p= 2·2r+2·r\pi$
$\small 2p= 4×12+2×12\pi$
$\small 2p= 48+24\pi \approx{123,4}\,cm;$
area:
$\small A= 2r·2r+r^2\pi$
$\small A= 2×12×2×12+12^2\pi$
$\small A= 48×48+144\pi$
$\small A= 576+144\pi \approx{1028,39}\,cm^2.$
145)
Perimetro:
$\small 2p= \dfrac{14\pi}{2}+\dfrac{14\pi}{2}+2×\dfrac{14\pi}{2}$
$\small 2p= \dfrac{\cancel{14}^7\pi}{\cancel2_1}+\dfrac{\cancel{14}^7\pi}{\cancel2_1}+\cancel2×\dfrac{14\pi}{\cancel2}$
$\small 2p= 7\pi+7\pi+14\pi = 28\pi\,cm;$
area:
$\small A= \dfrac{d^2\pi}{2}$
$\small A= \dfrac{14^2\pi}{2}$
$\small A= \dfrac{\cancel{196}^{98}\pi}{\cancel2_1} = 98\pi\,cm^2.$
sviluppo L = 4r+2rπ = 48+24π cm ..(123,40)
area A = (2r)^2+πr^2 = 576+144π cm^2...(1.028,4)