64/(5+3)=8 L=8*5=40 l=8*3=24 2p=24*4=96cm
Rettangolo:
dimensione minore $= \dfrac{64}{3+5}×3 = \dfrac{\cancel{64}^8}{\cancel8_1}×3 = 8×3= 24\,cm.$
Quadrato:
lato $l= 24\,cm;$
perimetro $2p= 4×l = 4×24 = 96\,cm.$
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