Α = 1/2·18·24---> Α = 216 m^2
ipotenusa=√(18^2 + 24^2) = 30 m
perimetro=18 + 24 + 30 = 72 m
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Ipotenusa $i= \sqrt{24^2+18^2} = \sqrt{576+324} = \sqrt{900} = 30\,m$ (teorema di Pitagora);
perimetro $2p= C+c+i = 24+18+30 = 72\,m;$
area $A= \dfrac{C×c}{2} = \dfrac{24×18}{2} = 216\,m^2.$