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$b=lr=lo-5\,cm= \dfrac{2p-B-5}{3} = \dfrac{200-72-5}{3}=\dfrac{123}{3}=41\,cm;$
per cui:
base minore $b= 41\,cm;$
lato retto $lr= 41\,cm;$
lato obliquo $lo= 41+5 = 46\,cm.$
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