[Risolto] Gentilmente potreste aiutarmi

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$\big\{(1-0,\overline3)^2+\big[1,5^2×(0,25-0,1\overline6)+\frac{5}{16}\big]^2\big\}÷(1-0,\overline4)=$

$=\big\{\big(1-\frac{3-0}{9}\big)^2+\big[\big(\frac{15}{10}\big)^2×\big(\frac{25}{100}-\frac{16-1}{90}\big)+\frac{5}{16}\big]^2\big\}÷\big(1-\frac{4-0}{9}\big)=$

$=\big\{\big(1-\frac{3}{9}\big)^2+\big[\big(\frac{3}{2}\big)^2×\big(\frac{1}{4}-\frac{15}{90}\big)+\frac{5}{16}\big]^2\big\}÷\big(1-\frac{4}{9}\big)=$

$=\big\{\big(1-\frac{1}{3}\big)^2+\big[\frac{9}{4}×\big(\frac{1}{4}-\frac{1}{6}\big)+\frac{5}{16}\big]^2\big\}÷\big(\frac{9-4}{9}\big)=$

$=\big\{\big(\frac{3-1}{3}\big)^2+\big[\frac{9}{4}×\big(\frac{3-2}{12}\big)+\frac{5}{16}\big]^2\big\}÷\frac{5}{9}=$

$=\big\{\big(\frac{2}{3}\big)^2+\big[\frac{9}{4}×\frac{1}{12}+\frac{5}{16}\big]^2\big\}×\frac{9}{5}=$

$=\big\{\frac{4}{9}+\big[\frac{3}{4}×\frac{1}{4}+\frac{5}{16}\big]^2\big\}×\frac{9}{5}=$

$=\big\{\frac{4}{9}+\big[\frac{3}{16}+\frac{5}{16}\big]^2\big\}×\frac{9}{5}=$

$=\big\{\frac{4}{9}+\big[\frac{8}{16}\big]^2\big\}×\frac{9}{5}=$

$=\big\{\frac{4}{9}+\big[\frac{1}{2}\big]^2\big\}×\frac{9}{5}=$

$=\big\{\frac{4}{9}+\frac{1}{4}\big\}×\frac{9}{5}=$

$=\big\{\frac{16+9}{36}\big\}×\frac{9}{5}=$

$=\frac{25}{36}×\frac{9}{5}=$

$=\frac{5}{4}×\frac{1}{1}=$

$=\frac{5}{4}$