Potete risolvere per favore
Es 275 per la prima grazie
Potete risolvere per favore
Es 275 per la prima grazie
((1/9)^4)^4/((1/9)^5·(1/9)^2·(1/9)^3)=
posto Α = 1/9
=(Α^4)^4/(Α^5·Α^2·Α^3)=
=Α^16/Α^10 = Α^6
Quindi:
(1/9)^6 = 1/3^12 =(1/3)^12
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$\small \left[\left(\dfrac{1}{9}\right)^4\right]^4 : \left[\left(\dfrac{1}{9}\right)^5×\left(\dfrac{1}{9}\right)^2×\left(\dfrac{1}{9}\right)^3\right] =$
$\small = \left(\dfrac{1}{9}\right)^{4×4} : \left(\dfrac{1}{9}\right)^{5+2+3} =$
$\small = \left(\dfrac{1}{9}\right)^{16} : \left(\dfrac{1}{9}\right)^{10} =$
$\small = \left(\dfrac{1}{9}\right)^{16-10} =$
$\small = \left(\dfrac{1}{9}\right)^6 $