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(2/3-1/2+5/4)+(3/4+1/2-2/3)+(9/4-3/8)+1/8

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$ (\frac{2}{3}-\frac{1}{2}+\frac{5}{4})+(\frac{3}{4}+\frac{1}{2}-\frac{2}{3})+(\frac{9}{4}-\frac{3}{8})+ \frac{1}{8} = $

$ \frac{8-6+15}{12}+\frac{9+6-8}{12}+\frac{18-3}{8}+ \frac{1}{8} = $

$ \frac{17}{12}+\frac{7}{12}+\frac{15}{8}+ \frac{1}{8} = $

$ \frac{24}{12}+\frac{16}{8}= 2 + 2 = 4 $



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(2/3-1/2+5/4)+(3/4+1/2-2/3)+(9/4-3/8)+1/8

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$\small \left(\dfrac{2}{3}-\dfrac{1}{2}+\dfrac{5}{4}\right)+\left(\dfrac{3}{4}+\dfrac{1}{2}-\dfrac{2}{3}\right)+\left(\dfrac{9}{4}-\dfrac{3}{8}\right)+\dfrac{1}{8}=$

$\small =\left(\dfrac{8-6+15}{12}\right)+\left(\dfrac{9+6-8}{12}\right)+\left(\dfrac{18-3}{8}\right)+\dfrac{1}{8}=$

$\small =\dfrac{17}{12}+\dfrac{7}{12}+\dfrac{15}{8}+\dfrac{1}{8}=$

$\small =\dfrac{\cancel{24}^2}{\cancel{12}_1}+\dfrac{\cancel{16}^2}{\cancel8_1}=$

$\small = 2+2 = 4$

 

 

 

 
 



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