motive force Fm = ma*g*sin 55° = 26,51 N
opposite force Fo = g(mb*(sin 27°+cos 27°*0,11)+ma*cos 55°*0,11)
Fo = 9,806*(2,588+0,559+3,3*0,063) = 32,90 N > Fm
...which means that friction will prevent masses from any motion and, therefore, relevant acceleration will be equal to zero !!