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Question

[attach]101986[/attach] numero 286

LucianoP · Accepted Answer

((- 2·p^4·q^2)^3/(- 2·p^5·q^2)^2)^3/((6·p^6)^2/(18·p^5)^2·(1/3 + 1/6)^(-1)·((-3)^3/2))^3 =

=((- 8·p^12·q^6)/(4·p^10·q^4))^3/(36·p^12/(324·p^10)·(1/2)^(-1)·(- 27/2))^3=

=(- 2·p^2·q^2)^3/(p^2/9·2·(- 27/2))^3=

=(- 8·p^6·q^6)/(- 3·p^2)^3=

=(- 8·p^6·q^6)/(- 27·p^6)=

=8·q^6/27

LucianoP

(@lucianop)

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31/01/2025 21:05