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0

a.

[(5/3a^3b)^5:(5/6a^2)^5-ab(-2a^2b^2)^2](8/7b)

Risultato [0]

b.
[3/4a^3b^6c^3-(3/4ab^2)^2(1/36ab^2c^3)-(-1/4ab^2c)^3]:(-3/4ab^2c^2)

Risultato [-a^2b^4c]

 
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2 Risposte



1

 

$[(\frac{5}{3}a^3b)^5÷(\frac{5}{6}a^2)^5-ab(-2a^2b^2)^2](\frac{8}{7}b)$

 

$[(\frac{5^5}{3^5}a^{15}b^5)÷(\frac{5^5}{6^5}a^{10})-ab(-2^2a^4b^4)](\frac{8}{7}b)$

 

$[(\frac{5^5}{3^5}a^{15}b^5)÷(\frac{5^5}{(3*2)^5}a^{10})-ab(2^2a^4b^4)](\frac{8}{7}b)$

 

$[(\frac{2^5*3^5}{3^5}a^5b^5)-ab(2^2a^4b^4)](\frac{8}{7}b)$

 

$[(2^5a^5b^5)-(2^2a^5b^5)](\frac{8}{7}b)$

 

$[(32a^5b^5)-(4a^5b^5)](\frac{8}{7}b)$

 

$(28a^5b^5)(\frac{8}{7}b)=32a^5b^6$

 

 

 

 

 

$[\frac{3}{4}a^3b^6c^3-(\frac{3}{4}ab^2)^2(\frac{1}{36}ab^2c^3)-(-\frac{1}{4}ab^2c)^3]÷(-\frac{3}{4}ab^2c^2)$

 

$[\frac{3}{4}a^3b^6c^3-(\frac{9}{16}a^2b^4)(\frac{1}{36}ab^2c^3)+(\frac{1}{64}a^4b^6c^3)]÷(-\frac{3}{4}ab^2c^2)$

 

$[\frac{3}{4}a^3b^6c^3-(\frac{1}{16}a^2b^4)(\frac{1}{4}ab^2c^3)+(\frac{1}{64}a^4b^6c^3)]÷(-\frac{3}{4}ab^2c^2)$

 

$[\frac{3}{4}a^3b^6c^3-(\frac{1}{64}a^3b^6c^3)+(\frac{1}{64}a^4b^6c^3)]÷(-\frac{3}{4}ab^2c^2)$

 

$[\frac{3}{4}a^3b^6c^3]÷(-\frac{3}{4}ab^2c^2)$

 

$[\frac{3}{4}a^3b^6c^3]÷(-\frac{3}{4}ab^2c^2)=-a^2b^4c$



0

Mi confermi il testo?

[(5/3a^3b)^5:(5/6a^2)^5-ab(-2a^2b^2)^2](8/7b)

$[(\frac{5}{3}a^3b)^5÷(\frac{5}{6}a^2)^5-ab(-2a^2b^2)^2](\frac{8}{7}b)$

[3/4a^3b^6c^3-(3/4ab^2)^2(1/36ab^2c^3)-(-1/4ab^2c)^3]:(-3/4ab^2c^2)

$[\frac{3}{4}a^3b^6c^3-(\frac{3}{4}ab^2)^2(\frac{1}{36}ab^2c^3)-(-\frac{1}{4}ab^2c)^3]÷(-\frac{3}{4}ab^2c^2)$



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