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3/10+[(17/20-5/6-2/3)/(-3/2-5)ˆ2+8/13-4/5]ˆ3+[(1/7+3/4)/(-1/7+3/7)]

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$\frac{3}{10}+\big[\big(\frac{17}{20}-\frac{5}{6}-\frac{2}{3}\big)/\big(-\frac{3}{2}-5\big)^2+\frac{8}{13}-\frac{4}{5}\big]^3+\big[\big(\frac{1}{7}+\frac{3}{4}\big)/\big(-\frac{1}{7}+\frac{3}{7}\big)\big]=$

$=\frac{3}{10}+\big[\big(\frac{51-50-40}{60}\big)/\big(\frac{-3-10}{2}\big)^2+\frac{8}{13}-\frac{4}{5}\big]^3+\big[\big(\frac{4+21}{28}\big)/\frac{2}{7}\big]=$

$=\frac{3}{10}+\big[-\frac{39}{60}/\big(-\frac{13}{2}\big)^2+\frac{8}{13}-\frac{4}{5}\big]^3+\frac{25}{28}/\frac{2}{7}=$

$=\frac{3}{10}+\big[-\frac{13}{20}/\frac{169}{4}+\frac{8}{13}-\frac{4}{5}\big]^3+\frac{25}{28}×\frac{7}{2}=$

$=\frac{3}{10}+\big[-\frac{13}{20}×\frac{4}{169}+\frac{8}{13}-\frac{4}{5}\big]^3+\frac{25}{4}×\frac{1}{2}=$

$=\frac{3}{10}+\big[-\frac{1}{5}×\frac{1}{13}+\frac{8}{13}-\frac{4}{5}\big]^3+\frac{25}{8}=$

$=\frac{3}{10}+\big[-\frac{1}{65}+\frac{8}{13}-\frac{4}{5}\big]^3+\frac{25}{8}=$

$=\frac{3}{10}+\big[\frac{-1+40-52}{65}\big]^3+\frac{25}{8}=$

$=\frac{3}{10}+\big[-\frac{13}{65}\big]^3+\frac{25}{8}=$

$=\frac{3}{10}+\big[-\frac{1}{5}\big]^3+\frac{25}{8}=$

$=\frac{3}{10}+\big(-\frac{1}{125}\big)+\frac{25}{8}=$

$=\frac{3}{10}-\frac{1}{125}+\frac{25}{8}=$

$=\frac{300-8+3125}{1000}=$

$=\frac{3417}{1000}$