espressioni

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{1/7*[15/8-(3/5+19/6-9/4+3/20):15/9]}{(1+5/12)+[(7/5-3/20+4/3)+(1-1/2)]}Risultato3/4

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$\small \left\{\dfrac{1}{7}·\left[\dfrac{15}{8}-\left(\dfrac{3}{5}+\dfrac{19}{6}-\dfrac{9}{4}+\dfrac{3}{20}\right) : \dfrac{15}{9}\right]\right\}·\left\{\left(1+\dfrac{5}{12}\right)+\left[\left(\dfrac{7}{5}-\dfrac{3}{20}+\dfrac{4}{3}\right)+\left(1-\dfrac{1}{2}\right)\right]\right\}=$

$\small =\left\{\dfrac{1}{7}·\left[\dfrac{15}{8}-\left(\dfrac{36+190-135+9}{60}\right) : \dfrac{\cancel{15}^5}{\cancel9_3}\right]\right\}·\left\{\left(\dfrac{12+5}{12}\right)+\left[\left(\dfrac{84-9+80}{60}\right)+\left(\dfrac{2-1}{2}\right)\right]\right\}=$

$\small =\left\{\dfrac{1}{7}·\left[\dfrac{15}{8}-\dfrac{\cancel{100}^5}{\cancel{60}_3}·\dfrac{3}{5}\right]\right\}·\left\{\dfrac{17}{12}+\left[\dfrac{\cancel{155}^{31}}{\cancel{60}_{12}}+\dfrac{1}{2}\right]\right\}=$

$\small =\left\{\dfrac{1}{7}·\left[\dfrac{15}{8}-\dfrac{\cancel5^1}{\cancel3_1}·\dfrac{\cancel3^1}{\cancel5_1}\right]\right\}·\left\{\dfrac{17}{12}+\left[\dfrac{31}{12}+\dfrac{1}{2}\right]\right\}=$

$\small =\left\{\dfrac{1}{7}·\left[\dfrac{15}{8}-1\right]\right\}·\left\{\dfrac{17}{12}+\left[\dfrac{31+6}{12}\right]\right\}=$

$\small =\left\{\dfrac{1}{7}·\left[\dfrac{15-8}{8}\right]\right\}·\left\{\dfrac{17}{12}+\dfrac{37}{12}\right\}=$

$\small =\left\{\dfrac{1}{7}·\dfrac{7}{8}\right\}·\dfrac{54}{12}=$

$\small =\left\{\dfrac{1}{\cancel7_1}·\dfrac{\cancel7^1}{8}\right\}·\dfrac{\cancel{54}^9}{\cancel{12}_2}=$

$\small = \dfrac{1}{8}·\dfrac{9}{2}=$

$\small = \dfrac{9}{16}$

Dopo aver riprovato mi torna sempre così, per il risultato che hai indicato sicuramente l'espressione dovrebbe essere tutta sotto radice quadrata, infatti $\small \sqrt{\dfrac{9}{16}} = \dfrac{3}{4}$; prova a riguardare il testo della domanda e magari fai sapere.

Controlla se nel tuo testo l'espressione è impostata così:

$\small \sqrt{\left\{\dfrac{1}{7}·\left[\dfrac{15}{8}-\left(\dfrac{3}{5}+\dfrac{19}{6}-\dfrac{9}{4}+\dfrac{3}{20}\right) : \dfrac{15}{9}\right]\right\}·\left\{\left(1+\dfrac{5}{12}\right)+\left[\left(\dfrac{7}{5}-\dfrac{3}{20}+\dfrac{4}{3}\right)+\left(1-\dfrac{1}{2}\right)\right]\right\}}=$

Saluti.