(46/63ab^4c)•(42/23a^3b)•(-9/8abc^3)
(46/63ab^4c)•(42/23a^3b)•(-9/8abc^3)
(46/63ab^4c)•(42/23a^3b)•(-9/8abc^3)
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$\left(\dfrac{\cancel{46}^2}{\cancel{63}_3}ab^4c\right)·\left(\dfrac{\cancel{42}^2}{\cancel{23}_1}a^3b\right)·\left(-\dfrac{9}{8}abc^3\right)=$
$= \dfrac{\cancel4^1}{\cancel3_1}a^4b^5c·\left(-\dfrac{\cancel9^3}{\cancel8_2}abc^3\right) =$
$= -\dfrac{3}{2}a^5b^6c^4$
((46/63·a·b^4·c)·(42/23·a^3·b))·(- 9/8·a·b·c^3)=
=4·a^4·b^5·c/3·(- 9/8·a·b·c^3)=
=- 3·a^5·b^6·c^4/2