(8^3 ÷ 4^3 x 2^5) ÷ (2^4)^2 + (4^3 x 2^3)^4 ÷ (4 x 4^3)^3 - 2^2 x (2^5)^2
(8^3 ÷ 4^3 x 2^5) ÷ (2^4)^2 + (4^3 x 2^3)^4 ÷ (4 x 4^3)^3 - 2^2 x (2^5)^2
Si utilizzano le proprietà delle potenze.
Spero sia chiaro il procedimento ☺️
8^3/4^3·2^5/(2^4)^2 + (4^3·2^3)^4/(4·4^3)^3 - 2^2·(2^5)^2=
=2^3·2^5/2^8 + (4^3·2^3)^4/(4·4^3)^3 - 2^2·(2^5)^2=
=2^3·2^5/2^8 + (2^6·2^3)^4/(2^8)^3 - 2^2·2^10=
=2^8/2^8 + (2^6·2^3)^4/(2^8)^3 - 2^2·2^10=
=2^8/2^8 + (2^9)^4/(2^8)^3 - 2^2·2^10=
=1 + 2^36/2^24 - 2^2·2^10=
=1 + 2^12 - 2^12=
=1
Sono tutti multlipi di due