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[(2/3)² - (8/9+8/3)+(7/3)²]·[(1/7)²+(4/7-1)-(2/7)²]

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3

[4/9-32/9+49/9]*[1/49-3/7-4/49]

[21/9]*[-24/49]

(21/9*-24/49)

$3/3*-8/7$

$1*-8/7$

$-8/7$



3

((2/3)^2 - (8/9 + 8/3) + (7/3)^2)·((1/7)^2 + (4/7 - 1) - (2/7)^2)=

=(4/9 - 32/9 + 49/9)·(1/49 + (- 3/7) - 4/49)=

=7/3·(- 24/49)= - 8/7



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