[Risolto] Espressione

$\left \{ \left[ \left (\dfrac{7}{3}\cdot \dfrac{1}{8} -\dfrac{3}{4} \div 4 \right ) +\left(1-\dfrac{1}{25} \right )+ \dfrac{3}{2} \div \dfrac{5}{3} \right] \div \left[ \left (\dfrac{2}{5}- \dfrac{7}{30} \div\dfrac{7}{3}\right ) \cdot \dfrac{5}{6} +\dfrac{3}{4}\right] \right\}^2  + \left(  1-2/3 \right)^2 = $

$\left \{ \left[ \left (\dfrac{7}{24} -\dfrac{3}{16}\right ) \left(\dfrac{24}{25} \right )+ \dfrac{9}{10}\right]  \div \left[ \left (\dfrac{2}{5}- \dfrac{1}{10} \right ) \cdot \dfrac{5}{6} +\dfrac{3}{4}\right] \right\}^2 +\dfrac{1}{9}=$ 

$\left \{ \left[ \left (\dfrac{5}{48}\right ) \left(\dfrac{24}{25} \right )+ \dfrac{9}{10}\right]  \div \left[ \left (\dfrac{3}{10} \right ) \cdot \dfrac{5}{6} +\dfrac{3}{4}\right] \right\}^2 +\dfrac{1}{9}=$ 

$\left \{ \left[\dfrac{1}{10} + \dfrac{9}{10}\right]  \div \left[ \dfrac{1}{4}  +\dfrac{3}{4}\right] \right\}^2 +\dfrac{1}{9}=$ 

$\left \{1  \div 1 \right\}^2 +\dfrac{1}{9} = 1 +\dfrac{1}{9} = 10/9$ 

Non dovrei essermi perso pezzi per strada.