perimetro 2p = Al/h = 336/8 = 42 cm
semiperimetro p = 42/2 = 21 = a+3a/4 = 7a/4
lato a = 21 = 7*4 = 12 cm
lato b = 12*3/4 = 9 cm
1) Volume V
V = a*b*h = 8*9*12 = 864 cm^3
2) diagonale D
D = √8^2+9^2+12^2 = 17,0 cm
3)
parallelepipedo equivalente
V' = V = 864 cm^3
area base Ab = 6*8 = 48 cm^2
altezza h = 864/48 = 18 cm^2
superficie totale At = 2*(6+8)*18+6*8) = 600 cm^2
2p=336/8=42 21/(3+4)=3 L1=3*3=9 L2=3*4=12 Sb=12*9=108 V=108*8=864cm3
D=V 12^2+9^2+8^2=17cm Sb2=6*8=48 h=864/48=18 Sl2=28*18=504
St=504+2*48=600cm2