136)
$1,5×0,\overline{18}×1,\overline6-\dfrac{4}{11}=$
$= \dfrac{15}{10}×\dfrac{18-0}{99}×\dfrac{16-1}{9}-\dfrac{4}{11}=$
$= \dfrac{\cancel{15}^3}{\cancel{10}_2}×\dfrac{18}{99}×\dfrac{15}{9}-\dfrac{4}{11}=$
$= \dfrac{3}{2}×\dfrac{\cancel{18}^2}{\cancel{99}_{11}}×\dfrac{\cancel{15}^5}{\cancel{9}_3}-\dfrac{4}{11}=$
$= \dfrac{3}{2}×\dfrac{2}{11}×\dfrac{5}{3}-\dfrac{4}{11}=$
$= \dfrac{\cancel3^1}{\cancel2_1}×\dfrac{\cancel2^1}{11}×\dfrac{5}{\cancel3_1}-\dfrac{4}{11}=$
$= \dfrac{1}{1}×\dfrac{1}{11}×\dfrac{5}{1}-\dfrac{4}{11}=$
$= \dfrac{5}{11}-\dfrac{4}{11}=$
$= \dfrac{1}{11}$
==========================================
$0,\overline5×7,5 : 0,8\overline3 =$
$= \dfrac{5-0}{9}×\dfrac{75}{10} : \dfrac{83-8}{90} =$
$= \dfrac{5}{9}×\dfrac{\cancel{75}^{15}}{\cancel{10}_2} : \dfrac{75}{90}=$
$= \dfrac{5}{9}×\dfrac{15}{2} : \dfrac{\cancel{75}^5}{\cancel{90}_6}=$
$= \dfrac{5}{\cancel9_3}×\dfrac{\cancel{15}^5}{2} : \dfrac{5}{6}=$
$= \dfrac{5}{3}×\dfrac{5}{2} × \dfrac{6}{5}=$
$= \dfrac{5}{3}×\dfrac{\cancel5^1}{\cancel2_1} × \dfrac{\cancel6^3}{\cancel5_1}=$
$= \dfrac{5}{3}×\dfrac{1}{1} × \dfrac{3}{1}=$
$= \dfrac{5}{3}×\dfrac{3}{1}=$
$= \dfrac{5}{\cancel3_1}×\dfrac{\cancel3^1}{1}=$
$= \dfrac{5}{1}×\dfrac{1}{1}=$
$= 5$