1 + log₂(x² - 1) = 3log₈(3) + log₂(3x - 2)
C.E.
x² - 1 > 0. x²>1. x ∈ R. 3x-2>0. 3x>2. x>⅔
1 + log₂(x² - 1) = 3log₈(3) + log₂(3x - 2)
log₂(2) + log₂(x² - 1) = 3[log₂(3) / log₂(8)] + log₂(3x - 2)
log₂(2x²-2) = 3log₂(3)/3 + log₂(3x - 2)
log₂(2x²-2) = log₂(9x - 6)
2x² - 2 = 9x - 6
2x² - 9x + 4 = 0
x = 9/4 ± √(81 - 32) / 4
x = 9/4 ± 7/4. x₁ = 4. x₂ = ½
per le C.E. solo x₁ = 4 è accettabile