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$\small \log(x+2)-\log(x) = 1$
$\small \log_{10}(x+2)-\log_{10}(x)=1$
$\small \log_{10}(x+2)+\log_{10}\left(\dfrac{1}{x}\right)=1$
$\small \log_{10}(x+2)+\log_{10}\left(\dfrac{1}{x}\right)=1$
$\small \log_{10}\left(\dfrac{x+2}{x}\right)=1$
$\small \dfrac{x+2}{x}=10^1$
$\small \dfrac{x+2}{x}=10$
$\small x+2=10x$
$\small x-10x=-2$
$\small -9x=-2$
$\small 9x=2$
$\small \dfrac{\cancel9x}{\cancel9}=\dfrac{2}{9}$
$\small x=\dfrac{2}{9}$ $\Longrightarrow (= 0,\overline2).$